The mathematical constant e was originally “discovered” as the limit of the following sequence:

e=limn(1+1n)n.

The following theorem presents a useful generalization of this result.

Theorem: Suppose the sequence nan has a limit as n. Then limn(1+an)n=exp(limnnan).

Proof: Let x=limnnan.

limn(1+an)n=limn(1+xnn)nLet xn=nan=limm(1+1m)mxnLet m=n/xn=limm[(1+1m)m]xneab=eab=exf(a,x)=ax is continuous;xnx