In class last week, we discussed and practiced the rules of probability. In today’s lab, we will review these concepts.
Addition Rule: \(P(A \cup B) = P(A) + P(B) - P(A \cap B)\)
Complement Rule: \(P(A^C) = 1 - P(A)\)
Multiplication Rule: \(P(A \cap B) = P(A)P(B|A)\)
Law of Total Probability: \(P(A) = P(A \cap B) + P(A \cap B^c)\)
Bayes’ Rule: \(P(A|B) = \frac{P(A)P(B|A)}{P(A)P(B|A) + P(A^c)P(B|A^c)}\)
Sensitivity: \(P(Test+ | Disease+)\)
Specificity: \(P(Test- | Disease -)\)
False Positive: \(P(Test+| Disease -) = 1-Specificity\)
False Negative: \(P(Test-| Disease +) = 1-Sensitivity\)
Prevalence: \(P(Disease)\)
These two terms are very easily confused, but need to be kept separate as they mean two different things. Two outcomes are said to be independent if the probability of the first outcome does not change the probability of the second outcome.
This independence works both ways as the outcome of A will also not effect the outcome of B. Mutually exclusive on the other hand, is the idea that the two outcomes cannot occur simultaneously. That is, the intersection of the two events is always equal to zero. In terms of a Venn diagram the two circles will never overlap. Note that an event and it’s compliment are ALWAYS mutually exclusive (an event either happens or it doesn’t).
Are the years of study mutually exclusive?
If a football player is selected at random what is the probability that he is not a senior?
If you select a random football player and it is given that he is not a senior what is the probability of him being a sophomore?
What is the probability that I pull two juniors out randomly with replacement? Without replacement?
What assumption changed based on the question asked?
Gender | Healthy | Gingivitis | Perio | Total |
---|---|---|---|---|
Male | ||||
Female | ||||
Total |
Fill in the following table with the given information as COUNTS:
The probability that a person is male is 0.3749,
The probability that a person is both male and healthy is 0.1429,
The probability that a person is both male and has Perio is 0.1167,
The probability of being healthy is 0.4672,
The probability that a person is female and has Perio 0.1147
Calculate the probability that the participant is male or healthy.
What is the probability of being female and having either gingivitis or periodontal disease?
What is the probability of an individual having periodontal disease given that she is female?
Let H denote the event of having HIV, and T the event of testing positive. Express the information that is given in the problem in terms of the events H and T.
Find the probability that someone chosen at random from the population has HIV and tests positive. Interpret this as a rate per 10,000 people
If someone has HIV, what is the probability of testing negative?
What is the probability a person has the disease given that they tested positive (use Bayes’ rule).
To set up this equation, first write the information provided in the form of probability notation and identify the corresponding proportions. You should do this for prevalence of cancer, prevalence of no cancer, sensitivity, specificity, and false positive and false negative rates.
Now modify the Bayes’ rule formula to match the notation you wrote in part (a) to find the probability of breast cancer given that the test is positive.
Finally plug in and calculate the answer. Interpret the results.